public boolean anagram(String s, String t) { // write your code here s = s.toLowerCase(); t = t.toLowerCase(); int[] count_s = new int[26]; for(int i = 0; i < s.length(); i++){ if(s.charAt(i) == ‘ ‘) continue; count_s[s.charAt(i)-‘a’]++; } int[] count_t = new int[26]; for(int i = 0; i < t.length(); i++){ if(t.charAt(i) == ‘ ‘) […]